1000000)B=(I-1000000)*0.01+400000*0.015+200000*0.03+200000*0.05+100000*0.075+100000*0.1;printf("奖金总数:%f\n",B);}includevoidmain(" />
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C语言企业利润奖金问题

include
mian()
{
float B,I>=0;
scanf("%f",&I);

if(I<=100000) B=I*0.1;

else if(I<=200000) B=(I-100000)*0.075+100000*0.1;

else if(I<=400000) B=(I-200000)*0.05+100000*0.075+100000*0.1;

else if(I<=600000) B=(I-400000)*0.03+200000*0.05+100000*0.075+100000*0.1;

else if(I<=1000000) B=(I-600000)*0.015+200000*0.03+200000*0.05+100000*0.075+100000*0.1;

else
(I>1000000) B=(I-1000000)*0.01+400000*0.015+200000*0.03+200000*0.05+100000*0.075+100000*0.1;


printf("奖金总数:%f\n",B);
}



include
void main()
{
float B,I>=0;

scanf("%f",&I);

switch()

{
case 0: B=I*0.1;
break;

case 1: B=(I-100000)*0.075+100000*0.1;
break;

case 2: B=(I-200000)*0.05+100000*0.075+100000*0.1;
break;

case 3: B=(I-400000)*0.03+200000*0.05+100000*0.075+100000*0.1;
break;

case 4: B=(I-600000)*0.015+200000*0.03+200000*0.05+100000*0.075+100000*0.1;
break;

default: B=(I-1000000)*0.01+400000*0.015+200000*0.03+200000*0.05+100000*0.075+100000*0.1;

}
printf("奖金总数:%f\n",B);

}

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