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Chapter 4作业

Chapter 4作业
Chapter 4作业

1.Concern for the preservation of public property should not be confined to protecting it from thieves and wreckers.为保护公共财产的关注不应局限于防止偷盗和破坏。

2.We are enemies of all aggressive wars.我们是所有侵略战争的敌人。

3. There must be a clear recognition of the principles of equality between states.各国之间必须明确平等的原则。

4. The president strongly advocated a sharp increase in the missile and space programs.总统强烈主张提高在导弹和太空计划上的预支。

5. The two leaders had a serious and frank exchange of views on Sino-U.S. relations and world affairs.两国领导人就中美关系和国际事务问题认真、坦率地交换了意见,。

6. In the exchange of cultures throughout the world, the study of a foreign language is a must.随着国际文化不断交融,学习一门外语是很有必要的。

7.The use of atomic weapons is a clear violation of international law.使用核武器显然违反国际法。

8. The design calculations will serve as an illustrative application of the theory of semi-conductor devices.这个设计会用来说明半导体器件理论如何应用。

9.She is familiar with English.她英语很熟练。

10.We seek a better understanding through multiplication of our economic, cultural, scientific, technical, and human ties.通过我们的经济,文化,科学,技术和人类的关系寻求一个更好的理解。

11.In his early days he abandoned medicine for literature.他早年弃医从文。

12.I have full assurance of the reliability of the information.我已充分保证了信息的可靠性。

13.The meeting was a great success.这次会议圆满成功。

14.The situation cannot be otherwise because our friendship and cooperation are based on our common sincere adherence to the five principles of peaceful co-existence.我们在对和平共处五项原则共同的坚持促成了我们的友谊与联系,这是毋庸置疑的。

汉译英(转换为名词)

烟鬼heavy smoker

饭量大have a good appetite

受害最深Suffer the most

游泳健将Top Swimmer

早起的人Early Bird

善于观察Good Observer

不善说谎Not good at lying

英译汉(转换为动词)

a slow walker慢走

a fast runner疾跑

a slick talker聪明的交谈

a great joker从容地讲笑话

a clock-watcher守夜

the best hater痛恨

an idler变懒惰

a good loser渐渐失败

Page 54 汉译英

The enjoyment of reading or enjoying the pleasure of a book has always been regarded as a

personal accomplishment.If it is not a person to acquire the habit of reading, you will feel life is boring,for the few interaction with friends and the few thing which is only limited to what is happening around them.But when he picked up a book, he would be in a very different world.If that is a good book, he will soon be in touch with the most learned man in the world.The author will guide him to go ahead and take him to a different country or age or discuss some unheard of knowledge or topic to him.

语言学-Chapter4-课后练习答案

Chapter 4 Revision Exercises 1. What is syntax? Syntax is a branch of linguistics that studies how words are combined to form sentences and the rules that govern the formation of sentences. 2. What is phrase structure rule? The grammatical mechanism that regulates the arrangement of elements (i.e. specifiers, heads, and complements) that make up a phrase is called a phrase structure rule. The phrase structural rule for NP, VP, AP, and PP can be written as follows: NP→(Det) N (PP) ... VP→(Qual) V (NP) ... AP→(Deg) A (PP) ... PP→(Deg) P (NP) ... We can formulate a single general phrasal structural rule in which X stands for the head N, V, A or P. The XP rule: XP→(specifier) X (complement) 3. What is category? How to determine a word’s category? Category refers to a group of linguistic items which fulfill the same or similar functions in a particular language such as a sentence, a noun phrase or a verb. To determine a word's category, three criteria are usually employed, namely meaning, inflection and distribution. The most reliable of determining a word’s category is its distribution. 4. What is coordinate structure and what properties does it have? The structure formed by joining two or more elements of the same type with the help of a conjunction is called coordinate structure. It has four important properties: 1)there is no limit on the number of coordinated categories that can appear prior to the conjunction. 2) a category at any level (a head or an entire XP) can be coordinated. 3)coordinated categories must be of the same type. 4)the category type of the coordinate phrase is identical to the category type of the elements being conjoined. 5. What elements does a phrase contain and what role does each element play? A phrase usually contains the following elements: head, specifier and complement. Sometimes it also contains another kind of element termed modifier. The role each element can play:

工程热力学课后作业答案chapter4

工程热力学课后作业答案chapter4

1 p73 4-1 1kg 空气在可逆多变过程中吸热40kJ ,其容积增大为1102v v =,压力降低为8/12p p =,设比热为定值,求过程中内能的变化、膨胀功、轴功以及焓和熵的变化。 解:热力系是1kg 空气 过程特征:多变过程 ) 10/1ln()8/1ln()2/1ln()1/2ln(==v v p p n =0.9 因为 T c q n ?= 内能变化为 R c v 2 5= =717.5)/(K kg J ? v p c R c 5 727===1004.5)/(K kg J ? =n c ==--v v c n k n c 51=3587.5)/(K kg J ? n v v c qc T c u /=?=?=8×103 J 膨胀功:u q w ?-==32 ×103J 轴功:==nw w s 28.8 ×103J 焓变:u k T c h p ?=?=?=1.4×8=11.2 ×103J

2 熵变:1 2ln 12ln p p c v v c s v p +=?=0.82×103)/(K kg J ? 4-2 有1kg 空气、初始状态为MPa p 5.01=,1501=t ℃,进行下列过程: (1)可逆绝热膨胀到MPa p 1.02=; (2)不可逆绝热膨胀到MPa p 1.02=,K T 3002=; (3)可逆等温膨胀到MPa p 1.02=; (4)可逆多变膨胀到MPa p 1.02=,多变指数2=n ; 试求上述各过程中的膨胀功及熵的变化,并将各过程的相对位置画在同一张v p -图和s T -图上 解:热力系1kg 空气 (1) 膨胀功: ])12(1[111k k p p k RT w ---==111.9×103 J 熵变为0 (2))21(T T c u w v -=?-==88.3×103J 1 2ln 12ln p p R T T c s p -=?=116.8)/(K kg J ?

管理学原理Chapter4课后题答案复习进程

第三次作业 宋子瑶经济1503 41507663 2. 3.Describe in detail the six-step strategic management process. The strategy management process is a six-step process that encompasses strategy planning, implementation and evaluation. The first step is identifying the organization’ s current mission, goals and strategies. Every organization needs a mission-a statement of its purpose. Defining the mission forces managers to identify what it’ s in business to do. It’s also important for managers to identify the current goals and strategies for managers have a basis for assessing whether they need to be changed. The second step is doing an external analysis. Analyzing that environment is a critical step in the strategic management process. Once the managers’ve analyzed the environment, managers need to pinpoint opportunities that the organization can exploit and threats that it must counteract or buffer against. And opportunities are positive trends in the external environment and threats are negative trends. The third step is doing an internal analysis. The internal analysis provides important information about an organization’s specific resources and

货币金融学chapter 4英文习题

Economics of Money, Banking, and Financial Markets, 11e, Global Edition (Mishkin) Chapter 4 The Meaning of Interest Rates 4.1 Measuring Interest Rates 1) The concept of ________ is based on the common-sense notion that a dollar paid to you in the future is less valuable to you than a dollar today. A) present value B) future value C) interest D) deflation Answer: A AACSB: Application of Knowledge 2) The present value of an expected future payment ________ as the interest rate increases. A) falls B) rises C) is constant D) is unaffected Answer: A AACSB: Reflective Thinking 3) An increase in the time to the promised future payment ________ the present value of the payment. A) decreases B) increases

Chapter 4 Exercises 含答案

Chapter 4 From Word to Text I. Decide whether each of the following statements is true or false: 1. Grammatical sentences are formed following a set of syntactic rules. 2. The syntactic rules of any language are finite in number, but there is no limit to the number of sentences native speakers of that language are able to produce and comprehend. 3. An endocentric construction is also known as headed construction because it has just one head 4. Constituents that can be substituted for one another without loss of grammaticality belong to the same syntactic category. 5. In English syntactic analysis, four phrasal categories are commonly recognized and discussed, namely, noun phrase, verb phrase, infinitive phrase, and auxiliary phrase. 6. Number and gender are categories of noun and pronoun. 7. Word order plays an important role in the organization of English sentences. 8. Like English, modern Chinese is a SVO language. 9. In English the subject usually precedes the verb and the direct object usually follows the verb. 10. A noun phrase must contain a noun, but other elements are optional. ( 1-5 TTFTF 6-10 TTTTT ) II. There are four given choices for each statement below. Mark the choice that can best complete the statement: 1 The head of the phrase “the city Rome”is_______D___ A the city B Rome C city D the city and Rome 2. The phrase “on the half” belongs to __B______construction A endocentric B exocentric C subordinate D coordinate

4A朗文Chapter4和5知识点梳理

4A朗文Chapter4 和5知识点梳理【必讲知识点】 1. 辨析 few , afew , little , alittle : few极少,几乎没有表示“否定”意义接可数名词复数形式 afew少许表示“肯定”意义接可数名词复数形式 little极少,几乎没有表示“否定”意义接不可数名词 alittle少许表示“肯定”意义接不可数名称 2. fewer与less都可以表示“更少” (1) fewer后接可数名词的复数形式,是few的比较级 (2) less后接不可数名词,是little的比较级 3. 辨析 much , manP, somuch 与 somanP somuch如此多接不可数名词 somanP如此多接可数名词的复数形式 much许多接不可数名词 manP许多接可数名词的复数形式 4. alotof=lotsof 表示许多,后可接可数名词的复数形式以及不可数名词 5. stop 用法 stoptodo 停止去做另外一件事 stopdo ing 停止做某事(指手头的事)

6. Therebe句型的一般过去时 1 .肯定式 therebe句型的一般过去时表示过去某地或某时存在某人或某物,其一般过去时态的陈述句由“thewas /were +主语+地点状语+时间状语”构 成。therewas后接单数名词;therewere 后接复数名词。 例如: Therewasacar un derthetreeamome ntago. 冈H才这棵树下有一辆小轿车。 Thereweretwoforeig nteachers ino urschoollastPear. 去年我们学校有两名外教。 2 .否定式 therebe句型一般过去时的否定式是在动词 was或were的后面加not,可缩写为 wasn 't或 weren ' t。 例如: Therewasn ' tafilminthecinemalast night.昨晚电影院里没有演电影。 Thereweren ' tahwomendoctorsthen. 当时没有女大夫。 3 .一般疑问式及其回答 therebe句型一般过去时的一般疑问式是将动词was或were放在there之 、八 刖。

chapter 1_4单片机基础复习题与答案

单片机基础(第3版) 第1章计算机基础知识 (一)填空题 1.十进制数14对应的二进制数表示为(1110B),十六进制数表示为(0EH)。 十进制数-100的补码为(9CH),+100的补码为(64H)。 2.在一个非零的无符号二进制整数的末尾加两个0后,形成一个新的无符号二 进制整数,则新数是原数的(4)倍。 3.8位无符号二进制数能表示的最大十进制数是(255)。带符号二进制数 11001101转换成十进制数是(-51)。 4.可以将各种不同类型数据转换为计算机能处理的形式并输送到计算机中去 的设备统称为(输入设备)。 5.已知字符D的ASCII码是十六进制数44,则字符T的ASCII码是十进制数 (84)。 6.若某存储器容量为640KB,则表示该存储器共有(655360)个存储单元。 7.在计算机中,二进制数的单位从小到大依次为(位)、(字节)和(字),对 应的英文名称分别是(bit)、(Byte)和(Word)。 8.设二进制数A=10101101,B=01110110,则逻辑运算A∨B=(11111111),A ∧B=(00100100),A⊕B=(11011011)。 9.机器数01101110的真值是(110),机器数01011001的真值是(89),机器 数10001101的真值是(141(无符号数)或-115(带符号数)),机器数11001110的真值是(206(无符号数)或-50(带符号数))。 说明:机器数是指计算机中使用的二进制数,机器数的值称为真值。机器数可表示无符号数也可表示带符号数,其中计算机中的带符号数一般为补码形式。1000 1101若为无符号数,则其真值为+141;若为带符号数,由于最高位(符号位)为1,所以为负数(补码形式),则其真值为-115。 (二)单项选择题 1. 用8位二进制补码数所能表示的十进制数范围是(D) (A)-127 ~ +127 (B)-128 ~ +128

会计学:企业决策的基础exercises-chapter4答案

SOLUTIONS TO EXERCISES Ex 4–1 a. Book value b. Materiality c. Matching principle d. Unrecorded revenue e. Adjusting entries f. Unearned revenue g. Prepaid expenses h. None (This is an example of ―depreciation expense.‖) Ex. 4–2 Income Statement Balance Sheet Adjusting Entry a b NE I D NE I D c I NE I I NE I d NE I D NE I D e NE I D D NE D f I NE I NE D I Ex. 4–3 a. Rent Expense....................................................................................... 240,000 Prepaid Rent ........................................................................... 240,000 To record rent expense for May ($1,200,000 ÷ 5 months = $240,000 per month). b. Unearned Ticket Revenue .................................................................. 148,800 Ticket Revenue ....................................................................... 148,800 To record earning portion of season ticket revenue relating to May home games. Ex. 4–4 a. (1) Interest Expense (375) Interest Payable (375) $50,000 x 9% annual rate x 1/12 = $375. (2) Accounts Receivable .................................................................... 10,000 Consulting Fees Earned ................................................... 10,000 To record ten days of unbilled consulting fees at $1,000 per day. b. $2,250 ($50,000 x 9% x 6/12 = $2,250) c. $15,000 ($25,000 - $10,000 earned in December, 2002)

四年级朗文英语上 Chapter4 单元复习卷

班别:姓名:学号: 四年级朗文英语上 Chapter4 单元复习卷 一、选择题 ( )1.what did people 500 years ago ? Most pepple cotton clothes . A. wear , wear B. wear , wore C. wore , wore ( )2. did people travel ? Some people travelled by sedan chair . A. What B.How C.Where ( )3.How did people for things ? Most people with silver and gold . A. pay , paid B. pay , pay C. paid ,paid ( )4. did people live ? Some people in towns . A.What , live B.Where , live C.Where , lived ( )5. What did they 10 years ago ? They rice and meat . A.eat , eat B.ate , ate C. eat ,ate ( )6. people cook with gas 50 years ago ? No , They . A.Did ,didn,t . B.Do , don’t C.Did , don’t ( )7.How life 500 years ago ? A.was B.is C.were ( )8.What they celebrate 500 years ago ? They celebrated Chinese New Year . A.do B.is C. did ( )9.I very happy yesterday . A. am B. was C.were ( )10. My father horse last month . A.ride B.rode C.by 二、根据单词的正确形式填空 1.What (do,did)children do in their spare time 60 years ago? --Most children (play ,played) hide-and-seek. --Some people ( play,played) with bean bags. 2.What (do, did) people write with 100 years ago? --Most people ( write ,wrote) with brushes. --Some people (write ,wrote) with pens. 3. What _ __ (do,did) you do yesterday morning? --I (go ,went) to the museum. 4.How___ _(do , did)you go there?

chapter4+练习1

1、设A={2,4,6},A上的二元运算*定义为:a*b=max{a,b},则在中,单位元是( ),零元是( )。 2、设A={3,6,9},A上的二元运算*定义为:a*b=min{a,b},则在独异点中,单位元是( ),零元是( ); 3、设a是12阶群的生成元,则a2是( )次元素,a -3是( )次元素。 4、在一个群〈G,*〉中,若G中的元素a的次数是k,则a-1的次数是( )。 5、的子群的充分必要条件是( )。 6、在自然数集N上,下列哪种运算是可结合的?() (1) a*b=a-b(2) a*b=max{a,b}(3) a*b=a+2b(4) a*b=|a-b| 7、设G是所有3位二进制数构成的集合,关于异或运算,G中的单位元是(),011的逆元是()。 8、10阶群的子群的阶数只可能是()。 二、选择题 1、在N上定义几个二元运算,其中不满足结合律的是()。 A. a*b = a B. a*b=a+b-5 C. a*b=a+3b D. a*b=max{a,b} 2. 下面4个代数系统中构成群的是()。 A. B. C. <ρ(A),∪> D. 3.是群,下面子集中()不是它的子群。

A. {1,2,4,8} B. {1,12} C. {1,3,9} D. {1,5,8,12} 4. 下面集合关于相应的加法和乘法运算构成域的是( )。 A. {a+b 3√3| a, b ∈Z} B. {a+bi| a ,b ∈Q} C. {a+b √2| a, b ∈Z} D.{?? ?? ??d c b a | a ,b ,c ,d ∈Z} 三、证明题: 1、设是群,a ∈G 。令H={x ∈G|a·x=x·a }。试证:H 是G 的子 群。 2、设G={1,3,5,7},关于模8乘法运算,列出运算表,说明G 构成群。 3、试求中每个元素的阶。 4、设为半群,a ∈S 。令S a ={a i | i ∈Z + }。试证 的子半群。 5、设H 和K 都是G 的子群。证明:H∩K 也是G 的子群。 6、设H 和K 都是G 的有限子群,且|H|与|K|互素。试证:H∩K={e}。 7、有限群G 的每个元素的阶均能整除G 的阶。 8、设S=Q ?Q ,Q 为有理数集合,*为S 上的二元运算:对任意∈S,有 *=, 求出S 关于二元运算*的单位元,以及当a ≠0时,关于*的逆元。

第4章 作业

Chapter4 homework 一、Select the best answer based on this couese ( 选择题). 1.The computer memory system refers to _________ A.RAM B. ROM C. Main memory D.Register , main memory, cache, external memory 2.If the word of memory is 16 bits, which the following answer is right? A. The address width is 16 bits B. The address width is related with 16 bits C.The address width is not related with 16 bits D. The address width is not less than 16 bits 3.The characteristics of internal memory compared to external memory A. Big capacity, high speed, low cost B. Big capacity, low speed, high cost C. small capacity, high speed, high cost D. small capacity, high speed, low cost 4.On address mapping of cache, any block of main memory can be mapped to any line of cache, it is ___________ . A. Associative Mapping B. Direct Mapping C. Set Associative Mapping D. Random Mapping 5. Cache’s write-through polity means write operation to main memory _______. A. as well as to cache B. only when the cache is replaced C. when the difference between cache and main memory is found D. only when direct mapping is used 6. Cache’s write-back polity means write operation to main memory ______________. A. as well as to cache B. only when the relative cache is replaced C. when the difference between cache and main memory is found D. only when using direct mapping 7. On address mapping of cache, the data in any block of main memory can be mapped to fixed line of cache, it is _________________. A. associative mapping B. direct mapping C. set associative mapping D. random mapping 8. On address mapping of cache, the data in any block of main memory can be mapped to fixed set any line(way) of cache, it is _________________. A. associative mapping B. direct mapping C. set associative mapping D. random mapping 9. Computer memory is organized into a hierarchy. At the highest level are the ___________. A. registers B. cache C. main memory D. external memory 10. On address mapping of cache, the data in any block of main memory can be mapped to __________ of cache, it is direct mapping . A. any line B. fixed line C. fixed set any line D. A and B 11. The characteristics of external memory compared to internal memory are _______ . A.Big capacity, high speed, low cost B. Big capacity, low speed, low cost C. small capacity, high speed, high cost D. small capacity, high speed, low cost 12. Write _____ policy can result in memory write bottle-neck. A. back B. through C. from D. to 13.A 16KByte cache has a line size of four 32-bit words, the number of line is . A 210 B 10 C 28 D 8 14. If the address-length of memory is 16 bits, which the following answer is NOT right ? . A.The addressable unit is 16 bits B.The addressing range is 216 C.The maxmum possible memory capacity is determined D.The addressable unit is not related with 16 bits 15. Suppose that the word from location X in memory can be mapped any line in the cache, this mapping function is called _____________. A. associative Mapping B. direct Mapping C. set Associative Mapping D. random Mapping 16. The simplest technique is called _____________.Using this technique, all write operations are made to main memory as well as to the cache. A. write-back B. write-through C. write-invalidate D. write-update

chapter4习题

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Chapter 4 练习题

第四章练习题 I. Define the following terms (名词解释) : 1. Culture 6. Factual knowledge 2. Cultural sensitivity 7. Interpretive knowledge 3. Linguistic distance 8. Cultural values 4. Strategy of unplanned change 9. Cultural borrowing 5. Social institutions 10. Material culture II. Multiple Choice Questions (单项选择): 1.__________ is pervasive in all marketing activities; the marketer's efforts actually become a part of the __________. A. Resistance; opposition to change B. Culture; fabric of culture C. Acceptance; new global context D. Public relations; culture E. Change; marketing strategy 2._____________ is the human-made part of human environment. A. Sociology B. Psychology C. Culture D. Reference groups E. Cohort groups 3.The sum total of knowledge, beliefs, art, morals, law, customs, and any other capabilities and habits acquired by humans as members of society is called: A. Sociology B. Psychology C. Culture D. Reference groups E. Cohort groups 4.When marketers first introduced the PDA to the American consumer they performed the role of being a(n) _____________ because the cultural impact of the product became

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Chapter 4 Negotiation: Strategy and Planning Overview In this chapter, we discuss what negotiators should do before opening negotiations. Effective strategy and planning are the most critical precursors for achieving negotiation objectives. With effective planning and target setting, most negotiators can achieve their objectives; without them, results occur more by chance than by negotiator effort. Regrettably, systematic planning is not something that most negotiators do willingly. Although time constraints and work pressures make it difficult to find the time to plan adequately, for many planning is simply boring and tedious, easily put off in favor of getting into the action quickly. It is clear, however, that devoting insufficient time to planning is one weakness that may cause negotiators to fail. The discussion of strategy and planning begins by exploring the broad process of strategy development, starting with defining the negotiator’s goals and objectives then moves to developing a strategy to address the issues and achieve one’s goals. Finally, we address the typical stages and phases of an evolving negotiation and how different issues and goals will affect the planning process. Learning Objectives 1.Goals – The focus that drives a negotiation strategy. 2.Strategy –The overall plan to achieve one’s goals. 3.Getting ready to implement the strategy: The planning process. I.Goals – The Focus That Drives a Negotiation Strategy A.Direct effects of goals on choice of strategy 1.There are four important aspects to understand about how goals affect negotiations: a.Wishes are not goals, especially in negotiation. b.Goals are often linked to the other party’s goals. c.There are boundaries or limits to what goals can be.

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