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课时提升作业(五)
Unit3Section A
(20分钟50分)
Ⅰ.词汇运用(10分)
根据句意及首字母或汉语提示完成单词。
1. Don’t talk l in the library. Be quiet, please.
2. Ann is f than Sue. She likes telling jokes.
3. —There are several kids in the room. W one is your brother?
—The boy in white sports shoes.
4. —Who(赢得)the first prize in the dancing competition?
—Sue did.
5. Lucy is more(努力的)than Jane, so she gets better grades at school.
答案: 1. loudly 2. funnier 3. Which 4. won 5. hard-working
Ⅱ. 单项选择(10分)
1. (2013·威海模拟)—Do you want to buy the red one or the yellow one?
—I’ll take of them. The red one is for me and the yellow one is for my brother.
A. either
B. both
C. neither
D. all
2. (2013·滨州模拟)I really enjoyed your speech, there were some parts I didn’t quite understand.
A. because
B. for
C. until
D. though
3. —Bob, you are late for school. You should get here ten minutes. —Sorry, Mr. Zhang.
A. early
B. earlier
C. earliest
D. the earliest
4. —This camera is really cheap.
—The, the better. I don’t have much money.
A. cheap
B. expensive
C. cheaper
D. more expensive
5. —Who works, Lucy or Lily?
—Lucy does, I think.
A. careful
B. carefully
C. more careful
D. more carefully
答案: 1~5. BDBCD
Ⅲ. 完成句子(每空词数不限)(10分)
1. (2013·陕西中考)她在英语方面比她弟弟好得多。
She is much at English than her brother.
2. (2013·湛江中考)我们的教室和他们的一样大。
Our classroom is theirs.
3. 萨姆和他的弟弟都喜欢踢足球。
Sam his brother like playing soccer.
4. 人人都想在比赛中获胜。
Everyone in the match.
5. 苏珊比她的姐姐更友好。
Susan is her sister.
答案: 1. better 2. as big as 3. Both; and 4. wants to win 5. friendlier than Ⅳ. 补全对话(10分)
从方框中选择最佳选项完成对话, 有两项多余。
A. Is he funnier than you?
B. What does he look like?
C. He is very wild and noisy.
D. You look so happy today.
E. We have a new comer in our class.
F. I think he likes sports very much.
G. Is he your good friend?
A: Hey, Nick!1Any good news?
B: Yes. 2His name is Bob.
A: How do you like him?
B: He is very funny. I like him very much.
A: 3
B: He certainly is. He is much funnier than me.
A: Is he a little wild?
B: Yes. 4He has long hair and wears very cool clothes.
A: 5
B: Yes, he does. He is very athletic. And he is even better at basketball than me.
1. 2. 3. 4. 5.
答案: 1~5. DEACF
Ⅴ. 完形填空(10分)
I have a twin sister, Kitty. She has1hair than me. I
don’t like long hair. Many people think we2have lots of
things in common. I’m afraid this is not tru e. When my
parents’ friends come to our home, Kitty often sits there and
says3, but I like to talk with them. So she is4than me. Kitty likes reading, drawing and cooking. I just like swimming and playing basketball. She has5 hobbies than me, but she is not as strong6me. Because Kitty does7than me at school, my parents often say to me, “8Kitty is younger than you, you should learn9her. ”We do have some similarities(相似之处), however. For example, we 10like eating fast food, going shopping and listening to pop music.
1. A. longer B. long C. short D. shorter
2. A. can B. should C. must D. need
3. A. something B. nothing
C. anything
D. everything
4. A. quieter B. younger C. wilder D. busier
5. A. much B. more C. less D. fewer
6. A. than B. as C. to D. for
7. A. worse B. bad C. better D. good
8. A. If B. No matter
C. Although
D. As
9. A. with B. from C. as D. by
10. A. either B. all C. both D. two
答案: 1~5. ACBAB6~10. BCCBC
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课时作业(十一) 1.在等差数列{a n }中,已知a 1=2,a 2+a 3=13,则a 4+a 5+a 6等于( ) A .40 B .42 C .43 D .45 答案 B 解析 ∵a 2+a 3=13,∴2a 1+3d =13.∵a 1=2,∴d =3. 而a 4+a 5+a 6=3a 5=3(a 1+4d )=42. 2.在等差数列-5,-312,-2,-1 2,…中,每相邻两项之间插入一个数, 使之组成一个新的等差数列,则新数列的通项公式为( ) A .an =34n -23 4 B .an =-5-3 2(n -1) C .an =-5-3 4(n -1) D .an =5 4 n 2-3n 答案 A 解析 首项为-5,公差为-312+52=3 4, ∴an =-5+(n -1)·34=34n -23 4 . 3.若a ,b ,c 成等差数列,则二次函数y =ax 2+2bx +c 的图像与x 轴交点的个数是( ) A .0 B .1 C .2 D .1或2 答案 D 解析 ∵a 、b 、c 成等差,∴2b =a +c . ∴Δ=(2b )2-4ac =(a +c )2-4ac =(a -c )2≥0.
4.数列{an }中,a 1=15,3an +1=3an -2,那么该数列中相邻两项的乘积为负数的是( ) A .a 21和a 22 B .a 22和a 23 C .a 23和a 24 D .a 24和a 25 答案 C 解析 由3an +1=3an -2可知{an }为等差数列,又a 1=15, ∴an =15+(n -1)·(-23)=-23n +473=47-2n 3. 令an ·an +1<0,即47-2n 3· 47-n + 3<0. 可得452
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The third period(第三课时) Part A Let’s spell ?教学内容与目标 课时教学内容课时教学目标 Let’s spell ·能够感知并归纳o-e在单词中的发音规则 ·能够读出符合o-e发音规则的单词 ·能够根据单词的读音拼写出符合o-e发音规则的单词 ? 1. 能够感知并归纳o-e在单词中的发音规则。 2. 能够读出符合o-e发音规则的单词。 ?教学难点 能够根据单词的读音拼写出符合o-e发音规则的单词。?教学准备 PPT课件、语音例词单词卡等。 ?教学过程 Step 1: Warm-up & Lead-in 1. Enjoy a song. Play the song—Friends. Ask students to sing after the recording. (出示课件) 2. Let’s chant. Play the chant for “i-e” in Unit 2 on the PPT. Get students to chant together. (课件出示:教材P16 Let’s spell板块中Read, listen and chant 部分的chant内容) Play the chant for short sound of “o” on the PPT. Get students to chant together. (课件出示:PEP三下教材P40 Let’s spell板块中Listen,repeat and chant部分的chant内容) Step 2: Presentation 1. Read the words. T: Today, we have a new friend. Look! Show the picture of Mr Jones on the PPT.(课件出示:教材P26 Mr Jones的图片)Lead in the words of this section. T: Who is he? Teaching purpose 以歌曲来热身,可以使学生在韵律中集中注意力,并激发学生的学习兴趣,让学生在轻松欢快的氛围中准备本课内容的学习。吟唱两首和i-e及o相关的歌谣,在律动中复习o的短音发音规律,为本节课的语音教学做铺垫。 Teaching purpose 逐步出示语音例词,使学生在语境中理解词汇的含义。
课时作业3等差数列的概念和通项公式 时间:45分钟满分:100分 一、选择题(每小题5分,共35分) 1.已知数列{a n}的通项公式为a n=2 011-2 012n,则此数列() A.是首项为2 011的等差数列 B.是首项为-1且公差为2 012的等差数列 C.是公差为2 011的递增等差数列 D.是首项为-1且公差为-2 012的递减等差数列 【答案】 D 【解析】a1=-1,a n+1-a n=[2 011-2 012(n+1)]-(2 011-2 012n)=-2 012<0.故选D. 2.已知在数列{a n}中,a n+1-a n=2,且a1=2,则这个数列的第10项为() A.18B.19 C.20 D.21 【答案】 C 【解析】由条件知{a n}是公差为2的等差数列,故a10=a1+9d =2+9×2=20. 3.在等差数列{a n}中,a1+a5=10,a4=7,则数列{a n}的公差为() A.1 B.2 C.3 D.4 【答案】 B
【解析】∵a1+a5=10=2a3, ∴a3=5.故d=a4-a3=7-5=2. 4.在等差数列{a n}中,a1+a9=10,a2+a10=14,则a4的值为() A.3 B.6 C.8 D.10 【答案】 A 【解析】由a1+a9=10,a2+a10=14得d=2, ∵a1+a9=2a1+8d=10, ∴a1=-3,∴a4=-3+3×2=3. 5.已知递增的等差数列{a n}满足a1=1,a3=a22-4,则a n=() A.2n B.2n-1 C.n-1 D.2n+1 【答案】 B 【解析】设等差数列{a n}的公差为d(d>0). 由a3=a22-4得a1+2d=(a1+d)2-4,即1+2d=(1+d)2-4,d2=4.又{a n}是递增数列,所以d=2, 故a n=a1+(n-1)d=1+(n-1)·2=2n-1. 6.设S n是数列{a n}的前n项和,且S n=n2,则{a n}() A.是常数列B.是等差数列 C.是摆动数列D.非以上三种数列 【答案】 B
Ⅰ.阅读理解 A 体裁:说明文话题:海洋词数:318时间:7′ The sea is home to billions of plants and animals.Many live only near the sunlit surface.Oceanographers classify marine living beings by separating them into two main groups:plants and animals. There are two general types of plants found in the ocean,those having roots that are attached to the ocean bottom and those not having roots which simply drift about with the water.The rooted plants in the ocean are only found in shallow water because there is not enough sunlight to sustain photosynthesis(光合作用) in deeper waters.Since sunlight does not pass more than a few hundred feet into the ocean,most of the ocean is not capable of supporting rooted plants. The most plenty plants in the ocean are known as phytoplankton(浮游生物).These are usually single-celled,minute floating plants that drift throughout the surface waters of the ocean.To grow,phytoplankton need nutrients from the sea water and lots of sunlight. Marine animals are divided into three groups:zooplankton,nekton,and benthos.Zooplankton are drifting animals and are usually small,however,they can grow to fairly large size.For example,the jellyfish and the Portuguese man-of-war are examples of larger types of zooplankton which are unable to propel(推进) themselves effectively. Nekton are the free swimmers and probably the largest portion of familiar animals found in the ocean belong to this https://www.wendangku.net/doc/a416140291.html,mon fishes,the octopus,whales,eels and squid are all examples of nekton. The third type of sea animals spends its entire life on or in the ocean bottom.This
北京市西城区2016-2017学年度第一学期期末试卷 八 年 级 数 学 2017.1 试卷满分:100分,考试时间:100分钟 一、选择题(本题共30分,每小题3分) 下面各题均有四个选项,其中只有一个..是符合题意的. 1.下列二次根式中,最简二次根式是( ). A. B.18 2. 2015年9月14日,意大利物理学家马尔科?德拉戈收到来自激光干涉引力波天文台(LIGO )的系统自动提示邮件,一股宇宙深处的引力波到达地球,在位于美国华盛顿和烈文斯顿的两个LIGO 探测器上产生了-18410?米的空间畸变(如图中的引力波信号图像所 示),也被称作“时空中的涟漪”,人类第一次探测到了引力波的存在,“天空和以前不同了……你也听得到了.”这次引力波的信号显著性极其大,探测结果只有三百五十万分之一的误差. 三百五十万分之一约为0.000 000 285 7.将0.000 000 285 7用科学记数法表示应为( ). A .-82.85710? B. -72.85710? C . -62.85710? D. -60.285 710? 3.以下图形中,不是.. 轴对称图形的是( ). 4. 如图,在△ABC 中,∠B =∠C =60?,点D 在AB 边上,DE ⊥AB ,并与 AC 边交于点E . 如果AD=1,BC=6,那么CE 等于( ). A. 5 B. 4 C. 3 D. 2 5.下列各式正确的是( ). A. 6212121= x x x x --?= B. 623 31 x x x x --÷== C. 32332 2 () x xy x y y --== D. 1 3223y x x y -??= ???
课时作业(二) 1.在△ABC中,a=2b cos C,则这个三角形一定是() A.等腰三角形B.直角三角形 C.等腰直角三角形D.等腰或直角三角形 答案 A 2.已知△ABC中,AB=3,AC=1,且B=30°,则△ABC的面积等于() A. 3 2 B. 3 4 C. 3 2或 3 D. 3 4或 3 2 答案 D 3.在△ABC中,a=15,b=10,A=60°,则cos B=() A.-22 3 B. 22 3 C.- 6 3 D. 6 3 答案 D 解析依题意得0°
解析 由正弦定理a sin A =b sin B ,得1sin A =3 sin B . 又∵B =2A ,∴1sin A =3sin2A =3 2sin A cos A . ∴cos A =3 2,∴∠A =30°,∴∠B =60°,∠C =90°. ∴c =12+(3)2=2. 5.(2013·陕西)设△ABC 的内角A ,B ,C 所对的边分别为a ,b ,c ,若b cos C +c cos B =a sin A ,则△ABC 的形状为( ) A .锐角三角形 B .直角三角形 C .钝角三角形 D .不确定 答案 B 解析 ∵b cos C +c cos B =a sin A ,由正弦定理,得sin B cos C +sin C cos B =sin 2A ,∴sin(B +C )=sin 2A ,即sin A =sin 2A . 又∵sin A >0,∴sin A =1,∴A =π 2,故△ABC 为直角三角形. 6.在△ABC 中,角A 、B 、C 所对的边分别为a 、b 、c ,已知A =60°,a =3,b =1,则c 等于( ) A .1 B .2 C.3-1 D. 3 答案 B 7.已知△ABC 的面积为3 2,且b =2,c =3,则( ) A .A =30° B .A =60° C .A =30°或150° D .A =60°或120° 答案 D 8.已知三角形面积为1 4,外接圆面积为π,则这个三角形的三边
七年级上册英语unit3课时作业练 习 第1课时(Section A 1a-2d) 一、根据首字母及汉语提示完成单词。 1.That (铅笔)i s n o t m i n e. 2.T h i s i s h e r(盒子). 3.T h i s i s a(字典) 4.I s t h i s y o u r(书包)? 二、用括号内所给单词的适当形式填空。 1.E x c u s e(I),i s t h i s y o u r r u l e r? 2.-I s t h a t y o u r c u p?-N o,(m y)i s w h i t e. 3.—A r e t h o s e h i s E n g l i s h b o o k s?-N o,t h e y a r e(h e r). 4.T h a t i s n o t(J a n e)e r a s e r. 5.M y p a r e n t s a r e(t e a c h e r)i n a m i d d l e s c h o o l. 三、根据汉语意思完成下列句子。 1.这是一台电脑。 i s a c o m p u t e r. 2.那是一辆自行车。 i s a b i k e. 3.--这是一个双肩背包吗?--是的,它是。 -I s a b a c k p a c k?-,. 4.-喂,你是罗斯吗?-不,我是玛丽。
-H e l l o,i s R o s e?-,i s M a r y. 5.-谁在敲门?-是我。 -W h o i s k n o c k i n g a t t h e d o o r?-m e. 6.这是我的英语字典。 T h i s i s E n g l i s h. 7.那个铅笔盒是他的吗? t h a t p e n c i l b o x? 8.今天去公园怎么样? g o i n g t o t h e p a r k t o d a y? 9.那些不是玛丽的书。 M a r y’s b o o k. 四、句型转换。 1.T h i s i s m y p e n c i l b o x.(改为一般疑问句) p e n c i l b o x? 2.I s t h i s h i s g r e e n p e n?(做否定回答) 3.I s t h i s d i c t i o n a r y y o u r s?(改为复数句) t h e s e y o u r s? 4.t h i s,y o u r,i s,p e n?(连词成句) 5.T h e s e a r e y o u r p e n s.(改为同义句) T h e s e p e n s. 第2课时(S e c t i o n A G r a m m a r F o c u s–3c) 一、用适当的代词填空。
北京市西城区2019— 2020学年度第一学期期末试卷 八年级数学 试卷满分:100分,考试时间:100分钟 一、选择题(本题共30分,每小题3分) 下面各题均有四个选项,其中只有一个是符合题意的. 1.计算22-的结果是( ). A.14 B.14- C.4 D.4- 2.下列剪纸作品中,不是.. 轴对称图形的是( ). A B C D 3.在下列分解因式的过程中,分解因式正确的是( ). A.()xz yz z x y -+=-+ B. ()22 3232a b ab ab ab a b -+=- C. 232682(34)xy y y x y -=- D. 234(2)(x 2)3x x x x +-=+-+ 4.下列分式中,是最简分式的是( ). A .2xy x B .222x y - C .22x y x y +- D .22 x x + 5.已知一次函数(2)3y m x =-+的图象经过第一、二、四象限,则m 的取值范围是( ). A .0m < B .0m > C .2m < D .2m > 6.分式11x --可变形为( ). A .11x + B .11x -+ C .11x -- D .11 x - 7.若一个等腰三角形的两边长分别为2和4,则这个等腰三角形的周长是为( ). A. 8 B. 10 C. 8或10 D.6或12 8.如图,B ,D ,E ,C 四点共线,且△ABD ≌△ACE ,若∠AEC =105°, 则∠DAE 的度数等于( ). A. 30° B.40° C. 50° D.65°
9.如图,在△ABC 中,BD 平分∠ABC ,与AC 交于点D ,DE ⊥AB 于点E ,若BC =5,△BCD 的面积为5,则ED 的长为( ). A. 12 B. 1 C.2 D.5 10.如图,直线y =﹣+m 与直线y =n +5n (n ≠0)的交点的横坐标为 ﹣2,则关于的不等式﹣+m >n +5n >0的整数解为( ). A.﹣5 ,﹣4,﹣3 B. ﹣4,﹣3 C.﹣4 ,﹣3,﹣2 D. ﹣3,﹣2 二、填空题(本题共20分,第11~14题,每小题3分,第 15~18题,每小题2分) 11.若分式1 1-x 在实数范围内有意义,则x 的取值范围是 . 12.分解因式224x y -= . 13.在平面直角坐标系Oy 中,点P (-2,3)关于y 轴的对称点的坐标是 . 14.如图,点B 在线段AD 上,∠ABC =∠D , AB ED =.要使 △ABC ≌△EDB ,则需要再添加的一个条件是 (只需填一个条件即可). 15.如图,在△ABC 中,∠ABC =∠ACB , AB 的垂直平分线交AC 于点M , 交AB 于点N .连接MB ,若AB=8,△MBC 的周长是14 ,则BC 的长 为 . 16.对于一次函数21y x =-+,当-2≤x ≤3时,函数值y 的取值范围 是 . 17.如图,要测量一条小河的宽度AB 的长,可以在小河的岸边作 AB 的垂线 MN ,然后在MN 上取两点C ,D ,使BC =CD ,再 画出MN 的垂线DE ,并使点E 与点A ,C 在一条直线上,这时 测得DE 的长就是AB 的长,其中用到的数学原理是: _ . 18.甲、乙两人都从光明学校出发,去距离光明学校1500m 远的篮球馆打球,他们沿同一条 道路匀速行走,乙比甲晚出发4min .设甲行走的时间为t (单位:min ),甲、乙两人相距
高中数学学习材料 (灿若寒星 精心整理制作) 课时作业20 基本不等式 时间:45分钟 满分:100分 一、选择题(每小题5分,共35分) 1.a +b ≥2ab (a >0,b >0)中等号成立的条件是( ) A .a =b B .a =-b C .a =|b | D .|a |=b 【答案】 A 【解析】 由基本不等式成立的条件易知. 2.x 2+y 2=4,则xy 的最大值是( ) A.12 B .1 C .2 D .4 【答案】 C 【解析】 xy ≤x 2+y 2 2=2,当且仅当x =y =2或x =y =-2时,等号成立,∴xy 的最大值为2. 3.若a >b >1,P =lg a ·lg b ,Q =1 2(lg a +lg b ),R =lg a +b 2,则( ) A .R
C .Q