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2011年3月份二C改错题答案

2011年3月上机改错题

1、

#include

typedef struct aa

{ int data;

struct aa *next;

} NODE;

int fun ( NODE *h )

{ int max=-1;

NODE *p;

/***********found**********/

p=h ; p=h->next; /*h指向的是头节点，题目要求

不要头节点，那么我们从第2个结点

开始*/

while(p)

{ if(p->data>max )

max=p->data;

/***********found**********/

p=h->next ; p=p->next; /*链表中的指针后移*/

}

return max;

}

outresult(int s, FILE *pf)

{ fprintf(pf,"\nThe max in link : %d\n",s);}

NODE *creatlink(int n, int m)

{ NODE *h, *p, *s;

int i;

h=p=(NODE *)malloc(sizeof(NODE));h->data=9999;

for(i=1; i<=n; i++)

{ s=(NODE *)malloc(sizeof(NODE));

s->data=rand()%m; s->next=p->next;

p->next=s; p=p->next;

}

p->next=NULL;

return h;

outlink(NODE *h, FILE *pf)

{ NODE *p;

p=h->next;

fprintf(pf,"\nTHE LIST :\n\n HEAD ");

while(p)

{ fprintf(pf,"->%d ",p->data); p=p->next; }

fprintf(pf,"\n");

}

main()

{ NODE *head; int m;

head=creatlink(12, 100);

outlink(head , stdout);

m=fun(head);

printf("\nTHE RESULT :\n"); outresult(m, stdout);

}

2、

#include

double fun ( int m )

{ double y = 1.0 ;

int i ;

/**************found**************/

for(i = 2 ; i < m ; i++) for(i = 2 ; i < =m ; i++) /*根据题意循环条件

是i<=m*/

/**************found**************/

y -= 1 /(i * i) ; y -= 1.0 /(i * i) ; /*i 是整型等号右边都是整

型，得到结果也是整型，我

们想要的是实型所以，要求

1改成1.0*/ return( y ) ;

}

main( )

{ int n = 5 ;

printf( "\nThe result is %lf\n", fun ( n ) ) ;

}

#include

char* fun( char tt[] )

{

int i;

for( i = 0; tt[i]; i++ )

/**********found***********/

if(( 'a' <= tt[i] )||( tt[i] <= 'z' ) ) if(( 'a' <= tt[i] )&&( tt[i] <= 'z' ) ) /*很明显，

这个地方是并且，用&&*/

/**********found***********/

tt[i] += 32; tt[i] -= 32; /*小写变大写是减去32*/

return( tt );

}

main( )

{

char tt[81];

printf( "\nPlease enter a string: " );

gets( tt );

printf( "\nThe result string is:\n%s", fun( tt ) );

}

#include

float fun ( float num )

{ int s ;

float n, t, pi ;

t = 1 ; pi = 0 ; n = 1 ; s = 1 ;

/**************found**************/

while(t >= num) while(fabs(t) >= num) /*这里的t可能会是负数，

所以要取绝对值用函

数fabs() 来实现*/ {

pi = pi + t ;

n = n + 2 ;

s = -s ;

/**************found**************/

t = s % n ; t = s / n ; /*这里对应题目是除法*/ }

pi = pi * 4 ;

return pi ;

}

main( )

{ float n1, n2 ;

printf("Enter a float number: ") ;

scanf("%f", &n1) ;

n2 = fun(n1) ;

printf("%6.4f\n", n2) ;

}

#include

int fun(int *x,int y)

{

int t ;

/**************found**************/

t = x ; x = y ; t=*x; *x=y; /*这里的x是指针变量，

可以通过间址运算符*

来运算，*x 就是变量

a */

/**************found**************/

return(y) ; return t; /*返回的值给变量 b ，应

是原来 a 的内容，也就是

*x 的内容*/

}

main()

{

int a = 3, b = 8 ;

printf("%d %d\n", a, b) ;

b = fun(&a, b) ;

printf("%d %d\n", a, b) ;

}

#include

void fun (long s, long *t)

{ int d;

long sl=1;

/************found************/

t = 0; *t=0; /* t 是指针变量*/

while ( s > 0)

{ d = s%10;

/************found************/

if (d%2 == 0) if (d%2 != 0) /*这里应该是留下奇数*/ { *t = d * sl + *t;

sl *= 10;

}

s /= 10;

}

main()

{ long s, t;

printf("\nPlease enter s:"); scanf("%ld", &s);

fun(s, &t);

printf("The result is: %ld\n", t);

}

#include

int fun(int a,int b)

{ int r,t;

if(a

/************found************/

t=a; b=a; a=t;

}

r=a%b;

while(r!=0)

{ a=b; b=r; r=a%b; }

/************found************/

return(a); return (b); /*这里b 存放的最大公约数*/ }

main()

{ int num1, num2,a;

printf("Input num1 num2: "); scanf("%d%d",&num1,&num2);

printf("num1= %d num2= %d\n\n",num1,num2);

a=fun(num1,num2);

printf("The maximun common divisor is %d\n\n",a);

}

#include

/**************found**************/

fun (int n ) double fun (int n ) /*根据函数被使用的类

型，或者返回值得到

函数类型是double */

{ int a = 2, b = 1, c, k ;

double s=0.0 ;

for ( k = 1; k <= n; k++ )

{ s = s + 1.0 * a / b ;

/**************found**************/

c = a; a += b; b += c; c = a; a += b; b = c; /*根据题目要求来，看出来b

=c*/

}

return(s) ;

}

main( )

{ int n = 5 ;

printf( "\nThe value of function is: %lf\n", fun ( n ) ) ;

}

#include

#define N 10

int findmid(int a, int b, int c)

{ int t;

t = (a>b)?(b>c?b:(a>c?c:a)):((a>c)?a:((b>c)?c:b));

/**********found**********/

return b; retrun t; /*算了好久，算出来的t ，当然是返回

t 啦*/

}

void fun(int x[])

{ int i,a,b,c,t[N];

/**********found**********/

for(i=0;i

号结束*/

for(i=0;i

{ a=t[i];b=t[i+1];c=t[i+2];

/**********found**********/

t[i+1]=findmid(a,b,c); x[i+1]=findmid(a,b,c); /*最终结果要放在x 数组中*/ }

}

main()

{ int i, x[N]={6,5,7,23,18,5,8,21,45,38};

for(i=0; i

printf("\n");

fun(x);

for(i=0; i

printf("\n");

}

#include

/************found************/

void fun (long s, long t) void fun (long s, long * t) /*这里的t是指

针变量，应该定义的时候有*

{ long sl=10;

s /= 10;

*t = s % 10;

/************found************/

while ( s < 0) while ( s >0) /*很明显，这里的条件不对嘛*/

{ s = s/100;

*t = s%10*sl + *t;

sl = sl * 10;

}

main()

{ long s, t;

printf("\nPlease enter s:"); scanf("%ld", &s);

fun(s, &t);

printf("The result is: %ld\n", t);

}

#include

int fun ( int m )

{ int k = 2;

while ( k <= m && (m%k))

/************found************/

k++ k++; /*语句少了分号*/

/************found************/

if (m = k ) if (m == k ) /*这里是比较，不是赋值，要用

== 是两个等号*/ return 1;

else return 0;

}

main( )

{ int n;

printf( "\nPlease enter n: " ); scanf( "%d", &n );

if ( fun ( n ) ) printf( "YES\n" );

else printf( "NO!\n" );

}

#include

int fun(int m)

{ int i, k ;

for (i = m + 1 ; ; i++) {

for (k = 2 ; k < i ; k++)

/**************found**************/

if (i % k != 0) if (i % k == 0) /*这里是能被整除的

时候break*/

break ;

/**************found**************/

if (k < i) if (k >= i) /*内层的for循环的条

件不是break 结束

也就是从来没有被整

除过，最后得到的是

素数*/

return(i);

}

void main()

{

int n ;

n = fun(20) ;

printf("n=%d\n", n) ;

}

#include

int fun(double x[], int n)

{

/************found************/

int j, c=0, double xa=0.0; int j, c=0；double xa=0.0; /*定义完一种类型

之后，应该以分号结束*/ for (j=0; j

xa += x[j]/n;

printf("ave =%f\n",xa);

for (j=0; j

/************found************/

if (x[j] => xa) if (x[j] >= xa) /*大于等于的符号怎么

写，一定看清楚了哦*/

c++;

return c;

}

main ( )

{ double x[100] = {193.199, 195.673, 195.757, 196.051, 196.092, 196.596, 196.579, 196.763};

printf("%d\n", fun (x, 8));

}

#include

void fun(char *s)

{ int i,j;

for(i=0,j=0; s[i]!='\0'; i++)

if(s[i]>='0' && s[i]<='9')

/**********found**********/

s[j]=s[i]; s[j++]=s[i]; /*s[j] 被赋值了之后，j 要++运算，以便

s[j]是下一个元素*/

/**********found**********/

s[j]="\0"; s[j]=’\0’;/*这里是字符0 不是字符串0*/

}

main()

{ char item[80];

printf("\nEnter a string : ");gets(item);

printf("\n\nThe string is : \"%s\"\n",item);

fun(item);

printf("\n\nThe string of changing is : \"%s\"\n",item );

#include

#define M 10

int a[M][M] = {0} ;

/**************found**************/

void fun(int **a, int m) void fun(int a[M][M], int m) /*这里定义变量

能够接受具体二维数组

a[M][M] ，如果不知道怎

么定义，直接照抄数组原来

的定义都可以*/

{ int j, k ;

for (j = 0 ; j < m ; j++ )

for (k = 0 ; k < m ; k++ )

/**************found**************/

a[j][k] = k * j ; a[j][k] = (k +1)* (j+1) ; /*这里是根据题目要

求，大家可以算出来第一个数字应该怎么得

到*/

}

main ( )

{ int i, j, n ;

printf ( " Enter n : " ) ; scanf ("%d", &n ) ;

fun ( a, n ) ;

for ( i = 0 ; i < n ; i++)

{ for (j = 0 ; j < n ; j++)

printf ( "%4d", a[i][j] ) ;

printf ( "\n" ) ;

}

#include

long fun(int g)

{

/**********found**********/

switch(g); switch(g) /*switch() 后面没有分号*/ { case 0: return 0;

/**********found**********/

case 1 ;case 2 : return 1 ; case 1 : case 2 : return 1 ; /*case 1 后面应该

冒号case 之后必须有冒号*/ }

return( fun(g-1)+fun(g-2) );

}

main()

{ long fib; int n;

printf("Input n: "); scanf("%d",&n); printf("n = %d\n",n);

fib=fun(n);

printf("fib = %d\n\n",fib);

}

#include

double fun( double q )

{ int n; double s,t;

n = 2;

s = 2.0;

while (s<=q)

{

t=s;

/************found************/

s=s+(n+1)/n; s=s+(n+1.0)/n; /*这里的n 是整形，(n+1)/n 得到的

结果也肯定是整形，而我们要得到实

型/

n++;

}

printf("n=%d\n",n);

/************found************/

return s; return t ; /*如果是return s 根据循环条件会多

加了一项所以返回时加最后之前的t

}

main ( )

{

printf("%f\n", fun(50));

}

#include

int fun( int k )

{ int m=0, mc=0 ;

while ((k >= 2) && (mc < 10))

{

/************found************/

if ((k%13 = 0) || (k%17 = 0)) if ((k%13 == 0) || (k%17 = =0)) /*这里是比

较不是赋值，所以用两个连续的等号

==*/

{ m = m+ k; mc++; }

k--;

}

return m;

/************found************/

_____ } /*函数体结束的时候用} 结束*/

main ( )

{

printf("%d\n", fun (500));

}

#include

#define N 10

/************found************/

void fun(int a[], int m ) int fun(int a[], int m ) /* 根据

主函数调用fun函数的，可以看到

要求fun 函数返回的是个int 型*/ { int low=0,high=N-1,mid;

while(low<=high)

{ mid=(low+high)/2;

if(m

high=mid-1;

/************found************/

else If(m > a[mid]) else if(m > a[mid]) /*这里的if 是关

键字，关键字必须全部小写*/ low=mid+1;

else return(mid);

}

return(-1);

}

main()

{ int i,a[N]={-3,4,7,9,13,45,67,89,100,180 },k,m;

printf("a数组中的数据如下:");

for(i=0;i

printf("Enter m: "); scanf("%d",&m);

k=fun(a,m);

if(k>=0) printf("m=%d,index=%d\n",m,k);

else printf("Not be found!\n");

}

#include

#define MAXLINE 20

fun ( char *pstr[6])

{ int i, j ;

char *p ;

for (i = 0 ; i < 5 ; i++ ) {

/**************found**************/

for (j = i + 1, j < 6, j++) for (j = i + 1;j < 6; j++) /*for 循环里面必须是

2个分号，这是格式，必须记牢*/ {

if(strcmp(*(pstr + i), *(pstr + j)) > 0)

{

p = *(pstr + i) ;

/**************found**************/

*(pstr + i) = pstr + j ; *(pstr + i) = *(pstr + j) /* pstr + j 是地址，要通过

* 运算符取得这个地址对应的内容*/ *(pstr + j) = p ;

}

main( )

{ int i ;

char *pstr[6], str[6][MAXLINE] ;

for(i = 0; i < 6 ; i++) pstr[i] = str[i] ;

printf( "\nEnter 6 string(1 string at each line): \n" ) ;

for(i = 0 ; i < 6 ; i++) scanf("%s", pstr[i]) ;

fun(pstr) ;

printf("The strings after sorting:\n") ;

for(i = 0 ; i < 6 ; i++) printf("%s\n", pstr[i]) ;

}

#include

void fun(char *p, char *b)

{ int i, k=0;

while(*p)

{ i=1;

while( i<=3 && *p ) {

/**********found**********/

b[k]=p; b[k]=p; /* p是指针变量，要取得内容，要使用

* 运算符*/

k++; p++; i++;

}

if(*p)

{

/**********found**********/

b[k++]=" "; b[k++]=’’; /*空格字符就是单引号里面的一个空格*/ }

}

b[k]='\0';

}

main()

{ char a[80],b[80];

printf("Enter a string: "); gets(a);

printf("The original string: "); puts(a);

fun(a,b);

printf("\nThe string after insert space: "); puts(b); printf("\n\n");

}

#include

/************found************/

f( double x) double f( double x) /*根据函数被调用地

方决定函数的类型这里是double */ {

if (x == 0.0 || x == 2.0)

return 0.0;

else if (x < 0.0)

return (x -1)/(x-2);

else

return (x +1)/(x-2);

}

double fun( int n )

{ int i; double s=0.0, y;

for (i= -n; i<=n; i++)

{y=f(1.0*i); s += y;}

/************found************/

return s return s ；/*return 语句后面必须有分号（少了分号

了，看到没有啊）*/

}

main ( )

{

printf("%f\n", fun(5) );

}

#include

int fun( int high )

{ int sum = 0, n=0, j, yes;

/************found************/

while ((high >= 2) && (n < 10) while ((high >= 2) && (n < 10)) /*while 最后少了个)

有没有注意到。。。。。*/

{ yes = 1;

for (j=2; j<=high/2; j++ )

if (high % j ==0 ){

/************found************/

yes=0; break yes=0; break ; /*break 后面少个分号，应该

注意到了吧*/

}

if (yes) { sum +=high; n++; }

high--;

}

return sum ;

}

main ( )

{

printf("%d\n", fun (100));

}

#include

/************found************/

void fun( int k ) double fun( int k ) /*说到不想说了，函

数的类型就是被调用处的类型*/ { int n; double s, w, p, q;

n = 1;

s = 1.0;

while ( n <= k )

{ w = 2.0 * n;

p = w - 1.0;

q = w + 1.0;

s = s * w *w/p/q;

n++;

}

/************found************/

return s return s ; /*return 语句后面又少了分号*/ }

main ( )

{

printf("%f\n", fun (10));

}

#include

int fun (char *str,char *substr)

{ int i,j,k,num=0;

/************found************/

for(i = 0, str[i], i++) for(i = 0;str[i];i++) /*for 语句中有2个

分号，一定记住，格式背下来*/ for(j=i,k=0;substr[k]==str[j];k++,j++)

/************found************/

If(substr[k+1]=='\0') if(substr[k+1]=='\0') /*if 是关键字，关键

字必须都是小写字母*/

{ num++;

break;

}

return num;

}

main()

{

char str[80],substr[80];

printf("Input a string:") ;

gets(str);

printf("Input a substring:") ;

gets(substr);

printf("%d\n",fun(str,substr));

}

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